给定一个任意字符串，我如何将命令打包为bash？

Question

I have a pretty basic golang question.

Given an arbitrary string like "echo foo", or "CGO_ENABLED=0 go build -o ./bin/echo -a main.go", what is the idiomatic way to parse/run that command using os/exec?

The way that I got this working seems pretty hacky, and I'm looking for a more idiomatic approach.

userInput = "CGO_ENABLED=0 go build -o ./bin/echo -a main.go"
command := exec.Command("/bin/bash", "-c", userInput)
out, err := command.Output()
if err != nil {
    fmt.Println(err)
 }

Answer 1

Depending on how arbitrary and flexible your userInput string is, I might do something like this.

package main

import (
    "log"
    "os"
    "os/exec"
)

func main() {
    if err := os.Setenv("FOO", "bar"); err != nil {
        log.Println(err)
    }

    // As Dave C pointed out, exec.Command does this for you.
    // goAbsPath, err := exec.LookPath("go")
    // if err != nil {
    //   log.Println(err)
    // }

    // Pass whatever other arguments necessary.
    cmd := exec.Command("go", "version")
    if err = cmd.Run(); err != nil {
        log.Println(err)
    }
}

If nothing else, maybe os.Setenv and exec.LookPath might be useful to know about.