如何将int转换为十六进制[重复]

Question

This question already has an answer here:

• How can I convert from int to hex 3 answers

I follow the article about building blockchain in go: https://jeiwan.cc/posts/building-blockchain-in-go-part-2/ When I study the part 2, I can't run the code in the prepareDate function. It always throw up a error:

underfined: IntToHex.

This is my code:

    func (pow *ProofOfWork) prepareData(nonce int) []byte {

    data := bytes.Join(

     [][]byte{
            pow.block.PrevBlockHash,
            pow.block.Data,
            IntToHex(pow.block.Timestamp),
            IntToHex(int64(targetBits)),
            IntToHex(int64(nonce)),
        },
        []byte{},
    )

    return data
}

</div>

Answer 1

the article you linked contains an url to the full source code

in the file utils.go is the IntToHex function used

package main

import (
    "bytes"
    "encoding/binary"
    "log"
)

// IntToHex converts an int64 to a byte array
func IntToHex(num int64) []byte {
    buff := new(bytes.Buffer)
    err := binary.Write(buff, binary.BigEndian, num)
    if err != nil {
        log.Panic(err)
    }

    return buff.Bytes()
}