怎样才能把下列代码改成输出5个不一样的？

Question

#include

#include

#include

void getgh(unsigned char * dest1, const unsigned int len1)
{
const unsigned char allChar1[11] = "0123456789";
unsigned int cnt1, randNo1;
srand((unsigned int)time(NULL));
for (cnt1 = 0; cnt1<len1; cnt1++)
{
randNo1 = rand() % 10;
*dest1 = allChar1[randNo1];
dest1++;
}
}

main()
{ int i=0,n=5;
FILE *fp=fopen("data2.txt","a");
for(i=0;i<n;i++)
{
const unsigned int strlen1 = 10;
unsigned char gh[strlen1 + 1] = {};
getgh(gh, strlen1);
fprintf(fp,"%s\n", gh);

}
fclose(fp); //关闭文件
printf("已随机生成数据！");
return 0;
}

Answer 1

getgh(gh, strlen1); 
fprintf(fp,"%s\n", gh);
->
int i;
for (i = 0; i < n; i++)
{
getgh(gh, strlen1); 
fprintf(fp,"%s\n", gh);
}