doujing5150 2017-09-04 16:41
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创建流以在GO中读取巨大的字符串

I have a huge xml in a variable and a function to decode this xml. I can't use unmarshal because at a certain momment I need to read an element and add it immediately in the db.

Example:

db := mongo.Connect()

decoder := xml.NewDecoder(resp.Body)
defer resp.Body.Close()

for {
    token, _ := decoder.Token()
    if token == nil {
        break
    }

    switch se := token.(type) {
    case xml.StartElement:
    ...
}

But now I need to read from a string. So I don't have the resp.Body anymore but a string. The NewDecoder() function receives an io.Reader, so I think I can in read from a stream. How can I do this??

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  • dongxi1320 2017-09-04 16:43
    关注

    Turn any string into an io.Reader with the strings.NewReader method:

    reader := strings.NewReader("some string")
    
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