Golang游览运动平方根

I'm trying to figure out why 1e-10 is used in this code. I was running through the exercises and got stuck on Next, change the loop condition to stop once the value has stopped changing (or only changes by a very small delta). See if that's more or fewer iterations. After not figuring it out, I searched and found this solution by someone else.

In a lot of solutions, I saw 1e-10 as part of an if statement within the for loop. In Golang, does it mean that 1e is risen to the (-10) power? Is it like, automatic for Golang? So basically normally I'd assume it would be written as 1e^(-10)?

package main

import (
    "fmt"
    "math"
)

func Sqrt(x float64) float64 {
    z := float64(2.)
    s := float64(0)
    for i := 0; i < 10; i++ {
        z = z - (z*z - x) / (2 * z)
        if math.Abs(z-s) < 1e-10 {
            break
        }
        s = z
    }
    return z
}

func main() {
    fmt.Println(Sqrt(2))
    fmt.Println(math.Sqrt(2))
}

Thanks for any/all help one may provide!