将shell输出转换为float64？

Question

i am using shell with golang to access apache log file and get some data. first i used to write output to the file directly and it was working, but now i need to get the output and use it in the program directly. and also i need to convert it to float64. i tried converting it into a string and then to float64, but it is not working?

func Mem_usage_data(j int) (Mem_predict float64, err error) {
    awkPart := fmt.Sprintf("awk '{print $%d/1024}'", j)

    out1, err := exec.Command("bash", "-c", "tail -n 1 /var/log/apache2/access.log| "+awkPart+" ").Output()
    fmt.Println("memory usage is", out1)
    s1 := string(out1)
    v1, err1 := strconv.ParseFloat(s1, 64)
    if err1 != nil {
        fmt.Println(err)
    }
    if err != nil {
        fmt.Println(err)
    }
    return v1, err
}

when i print the out1 i get something like this [48 46 49 50 48 49 49 55 10]. CAn you please help how to get the exact output in out1 and how to convert it into float64?

Answer 1

The conversion fails probably because there is some whitespace or newline character on s1. Try to trim it first before doing the conversion. Use strings.TrimSpace() to achieve that.

v1, err1 := strconv.ParseFloat(strings.TrimSpace(s1), 64)