GoLang：创建一个接受接口的函数（我来自PHP）

Question

In PHP I can create an interface

interface Hello {
    public function bar();
}

And some classes that implements it

final class Foo implements Hello {
    public function bar() {
        // do something
    }
}

final class Bar implements Hello {
    public function bar() {
        // do something
    }
}

Then, I can also create a NewClass::bar() method that accept the interface.

final class NewClass {
    public function bar(Hello $hello) {
        // do something
    }
}

How can I do the same, in Golang?

type humanPlayer struct {
    name string
}

type botPlayer struct {
    name string
}

How can I realize same pattern in golang?

Answer 1

package main

import (
    "fmt"
)

type Namer interface {
    Name() string
}

type humanPlayer struct {
    name string
}

func (h *humanPlayer) Name() string {
    return h.name
}

type botPlayer struct {
    name string
}

func (b *botPlayer) Name() string {
    return b.name
}

func sayName(n Namer) {
    fmt.Printf("Hello %s
", n.Name())
}

func main() {
    human := &humanPlayer{
        name: "bob",
    }
    bot := &botPlayer{
        name: "tom",
    }
    sayName(human)
    sayName(bot)
}