字符串切片的范围不一致

Question

This code:

import "fmt"
import "time"
func main() {
    string_slice:=[]string{"a","b","c"}

    for _,s:=range string_slice{
        go func(){
            time.Sleep(1*time.Second)
            fmt.Println(s)
        }()
    }

    time.Sleep(3*time.Second)
}

produces the output "c c c", while this code:

import "fmt"
func main() {
    string_slice:=[]string{"a","b","c"}

    for _,s:=range string_slice{
        s="asd"
        fmt.Println(s)
    }
    fmt.Println(string_slice)
}

produces the output "[a b c]"

The first one would suggest that for range iterates over references (which it should not), and the second one suggests that it iterates over copies of values (which it should).

Why doesn't the first one produce the output "a b c"?

Answer 1

When uses goroutine you must assume that it will running in parallelo. So in this case might occur 'c c c' as too 'b b b' or 'a a a'

On run in 3 times this code:

for _,s:=range string_slice \un t0, t1, t2 

You will send for running 3 times this code:

go func(){
  fmt.Println(s)
}()//send in t0, t1, t2

So, might occur of func() start running in t2, per example. In this case the result will 'c c c' because s equals latest value (string_slice[2]).

The solution is copy value by func params:

for _, s := range string_slice{
    go func(x string){
        time.Sleep(1*time.Second)
        fmt.Println(x)
    }(s)
}

Or create new value per iteration

//creating new value per iteration
for i := range string_slice{
    s := string_slice[i]
    go func(){
        time.Sleep(1*time.Second)
        fmt.Println(s)
    }()
}

See working in https://play.golang.org/p/uRD6Qy6xSw