duanqujing3863 2018-03-10 04:58
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Golang中的数组分配:内容副本或内容指针副本

While learning nuances of array data structure in Golang I came across an interesting confusion. I have learnt from blog.golang.org that -

when you assign or pass around an array value you will make a copy of its contents.

To check this myself I wrote the following piece of code:

package main

import "fmt"

func main() {
    x := []int{2, 4, 5}
    y := x

    y[0] = -10

    // expecting 2 here but getting -10, since  y := x is supposed to be a content copy
    fmt.Println(x[0])

    // not same
    println("&x: ", &x)
    println("&y: ", &y)

    // same
    println("&x[0]: ", &x[0])
    println("&y[0]: ", &y[0])
}

Doing exactly same thing is java I got same internal object address for x and y as expected.

Go Code: https://play.golang.org/p/04l0l84eT4J

Java code: https://pastebin.ubuntu.com/p/S3fHMTj5NC/

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1条回答 默认 最新

  • dongxiao0449 2018-03-10 05:14
    关注

    Your x:

    x := []int{2, 4, 5}
    

    is a slice, not an array.

    If you make x an array:

    x := [3]int{2, 4, 5}
    // ---^ Now it is an array
    

    then you'll see the results you're expecting:

    package main
    
    import "fmt"
    
    func main() {
        x := [3]int{2, 4, 5}
        y := x
    
        y[0] = -10
    
        // expecting 2 here, since it is supposed to be a content copy
        fmt.Println(x[0])
    
        // not same
        fmt.Println("&x: ", &x)
        fmt.Println("&y: ", &y)
    
        // same (not anymore...)
        fmt.Println("&x[0]: ", &x[0])
        fmt.Println("&y[0]: ", &y[0])
    }
    

    produces output like this:

    2
    &x:  &[2 4 5]
    &y:  &[-10 4 5]
    &x[0]:  0x10414020
    &y[0]:  0x10414030
    

    https://play.golang.org/p/-3ZNPwlD1WT

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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