duanfan9859 2014-09-16 22:45
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如何在Golang中将[] byte XML转换为JSON输出

Is there a way to convert XML ([]byte) to JSON output in Golang?

I've got below function where body is []byte but I want to transform this XML response to JSON after some manipulation. I've tried Unmarshal in xml package with no success:

// POST 
func (u *UserResource) authenticateUser(request *restful.Request, response *restful.Response) {
    App := new(Api)
    App.url = "http://api.com/api"
    usr := new(User)
    err := request.ReadEntity(usr)
    if err != nil {
        response.AddHeader("Content-Type", "application/json")
        response.WriteErrorString(http.StatusInternalServerError, err.Error())
        return
    }

    buf := []byte("<app version=\"1.0\"><request>1111</request></app>")
    r, err := http.Post(App.url, "text/plain", bytes.NewBuffer(buf))
    if err != nil {
        response.AddHeader("Content-Type", "application/json")
        response.WriteErrorString(http.StatusInternalServerError, err.Error())
        return
    }
    defer r.Body.Close()
    body, err := ioutil.ReadAll(r.Body)
    response.AddHeader("Content-Type", "application/json")
    response.WriteHeader(http.StatusCreated)
//  err = xml.Unmarshal(body, &usr)
//  if err != nil {
//      fmt.Printf("error: %v", err)
//      return
//  }
    response.Write(body)
//  fmt.Print(&usr.userName)
}

I'm also using Go-restful package

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2条回答

  • ds000001 2016-01-28 22:59
    关注

    If you need to convert an XML document to JSON with an unknown struct, you can use goxml2json.

    Example :

    import (
      // Other imports ...
      xj "github.com/basgys/goxml2json"
    )
    
    func (u *UserResource) authenticateUser(request *restful.Request, response *restful.Response) {
      // Extract data from restful.Request
      xml := strings.NewReader(`<?xml version="1.0" encoding="UTF-8"?><app version="1.0"><request>1111</request></app>`)
    
      // Convert
        json, err := xj.Convert(xml)
        if err != nil {
            // Oops...
        }
    
      // ... Use JSON ...
    }
    

    Note : I'm the author of this library.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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