如何获取类型函数的方法字段（开始）

Question

I'm wondering if it's possible to get the method fields from a typed function using reflection or by other means. The problem that I'm trying to solve is that I have a method which accepts a function of specific type but I need to actually transport different types and based on the type provided to execute operations. I'm aware that I could use an interface{} value as receiver but I don't want to loose the type checking on the calling function ("GetIt")

package main

type ttp struct {
    Coupons string
}

func (m ttp) GetIt(x string) {
    if m.Coupons != "" {
        print(m.Coupons)
    }
}

func calculate(mth func(s string)){
    //perform calculations and update the Coupon field
    mth.Cupons = "one coupon" // is not working :(
    // execute it again with the processed value
    mth.GetIt() // is not working


}
func main() {
    m := ttp{Coupons: "something"}
    calculate(m.GetIt)
}

Play

Answer 1

well this does not answer your exact question but it should solve your problem and cleanup the logic: push the calculate method inside the type and use a interface

https://play.golang.org/p/On_AigRYW6

package main

import "fmt"

type Computer interface {
    Compute(string)
}

type myp struct {
    Coupons string
}

// myp implements Computer
func (m *myp) Compute(x string) {
    m.GetIt(x)
    fmt.Println("myp")

}

type ttp struct {
    Various string
}

// ttp implements Computer
func (m *ttp) Compute(x string) {
    m.GetIt(x)
    fmt.Println("ttp")
}

func (m myp) GetIt(x string) {}
func (m ttp) GetIt(x string) {}

func main() {
    m := &myp{Coupons: "something"}
    t := &ttp{Various: "various stuff"}
    var stuff = []Computer{m, t}
    for _, c := range stuff {
        c.Compute("s")
    }
}