dongmeng2509 2017-11-28 06:28
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在Go select构造中,是否可以在两个case语句中向非缓冲通道发送和接收?

I am expecting this code to go in an infinite loop, sending and receiving the message. But it does not seem to either send or receive. Why?

go func() {
    for {
        select {
        case ch1 <- 1:
            println("sent 1 ")
        case c := <-ch1:
            println(" received ", c)
        }
        time.Sleep(time.Second)
    }
}()
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  • duanmengmiezen8855 2017-11-28 07:01
    关注

    The channel documentation says:

    If the capacity is zero or absent, the channel is unbuffered and communication succeeds only when both a sender and receiver are ready.

    The select documentation says:

    If one or more of the communications can proceed, a single one that can proceed is chosen via a uniform pseudo-random selection.

    The receive case cannot proceed because there's not a ready sender. The send case cannot proceed because there's not a ready receiver. The program deadlocks in the select.

    A single goroutine cannot make the send and receive both ready because the goroutine can only execute one branch of the select at a time.

    The program will loop forever if the channel is buffered (playground example).

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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