请问怎么处理“表达式必须是可修改的左值”的问题？

Question

#include
int main()
{
const int size = 3;
int board[size][size];

int i, j;
int numofx;
int numofo;
int result = -1;//-1:没人赢，1：x赢，0：o赢
for (i = 0; i < size; i++)
{
    for (j = 0; j < size; j++)
    {
        scanf("%d", &board[i][j]);
    }
}// 数组初始化(读入矩阵)
    for (i = 0; i < size && result == -1; i++)
    {
        numofo = numofx = 0;
        for (j = 0; j < size; j++)
        {
            if (board[i][j] == 1)
            {
                numofx++;
            }
            else
            {
                numofo++;
            }
        }
        if (numofo == size)
        {
            result = 0;
        }
        else if (numofx == size)
        {
            result = 1;
        }
    }//检查行
    if (result = -1)
    {
        for (j = 0; j < size && result = -1; j++)
        {
            numofo = numofx = 0;
            for (i = 0; i < size; i++)
            {
                if (board[i][j] == 1)
                {
                    numofx ++;
                }
                else
                {
                    numofo ++;
                }
            }
            if (numofo == size)
            {
                result = 0;
            }
            else if (numofx == size)
            {
                result = 1;
            }
        }
    }

Answer 1

result = -1
->
result == -1

问题解决的话，请点下采纳