dongpo2340 2018-02-09 05:33
浏览 44
已采纳

Golang结构指针调用接口方法

I'm picking up Golang and I've got a problem in traversing a linked list. What I intend to do is visit all nodes of the linked list, and call an interface method from each node.

I've defined an interface

type Sortable interface {
    CompareTo(t Sortable) int
}

I've defined a node type and a linked list

type node struct {
    pNext *node
    value int
}

type LinkedList struct {
    PHead, PNode *node
}

func (n node) CompreTo(t Sortable) int{
    other := t.(node)
    if n.value == other.value {
        return 0
    } else if n.value > other.value {
        return 1
    } else {
        return -1
    }
}

The problem occurs when I'm doing a comparison while traversing the linked list: ......

PNode.CompareTo(PNode.pNext)

and I get: panic: interface conversion: Sortable is *node, not node

Guess this is because PNode and PNode.pNext are pointers to the node struct, not node objects? Then how should I cast the pointer to make it right? I used to write in C++ so maybe my strategy goes wrong in Golang world?

Any advice is appreciated!

  • 写回答

1条回答 默认 最新

  • dslh32311 2018-02-09 05:49
    关注

    You have to assert the Sortable t to a pointer node.

    func (n node) CompreTo(t Sortable) int{
        other := t.(*node)
        if n.value == other.value {
            return 0
        } else if n.value > other.value {
            return 1
        } else {
            return -1
        }
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 请问这个是什么意思?
  • ¥15 STM32驱动继电器
  • ¥15 Windows server update services
  • ¥15 关于#c语言#的问题:我现在在做一个墨水屏设计,2.9英寸的小屏怎么换4.2英寸大屏
  • ¥15 模糊pid与pid仿真结果几乎一样
  • ¥15 java的GUI的运用
  • ¥15 我想付费需要AKM公司DSP开发资料及相关开发。
  • ¥15 怎么配置广告联盟瀑布流
  • ¥15 Rstudio 保存代码闪退
  • ¥20 win系统的PYQT程序生成的数据如何放入云服务器阿里云window版?