doubi9255 2017-10-14 22:55
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初学者级代码死锁

here is my main function's body;

c := make(chan int)

go func() {

    i := <-c
    i++
    time.Sleep(100 * time.Millisecond)

    c <-i


}()

time.Sleep(1 * time.Second)
go func() {
    i := <-c
    i++
    time.Sleep(100 * time.Millisecond)
    c <-i

}()

time.Sleep(1 * time.Second)
fmt.Println(<-c)

i am getting deadlock error.even i've tried with waitgroups.hella ripped my hair.

explaining answer would be great for me.

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3条回答 默认 最新

  • doudao1837 2017-10-15 06:26
    关注

    Add before the last line:

    c <- 0
    

    This way you give start value which could be read by goroutines to start working. Also you can add to both goroutines before the last line (sending to channel) add printing goroutine number and value:

    fmt.Println("goroutine 1 value", i)
    

    This you can see how values are passed in situation of 3 possible consumers of the same item in channel. Most likely the main goroutine will read the channel and you get 0. Add Sleep to give others a chance. Play with sleep time toget different results.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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