如何在Python中类似于Go中的“ crypto / md5”来计算字符串的md5

Question

I know there is hashlib in Python, but I want to achieve the same result as in Go below:

package main

import (
    "crypto/md5"
    "fmt"
)

func main() {
    data := []byte("12345")
    fmt.Println("sum ", md5.Sum(data))
}

As func md5.Sum described, it calculates "MD5 checksum of the data". However, I don't find any similar function in Python.

Is there any way to achieve md5.Sum in Python as in Go?

The output of program above is a slice other than a string:

sum  [32 44 185 98 172 89 7 91 150 75 7 21 45 35 75 112]

Answer 1

Based on PM 2Ring's solution, here is a working program,

from hashlib import md5

hexv = md5(b'12345').hexdigest()
l = [str(int(i+j,16)) for i, j in zip(hexv[::2], hexv[1::2])]
print("sum [" + ", ".join(l)+"]")

This prints,

sum [130, 124, 203, 14, 234, 138, 112, 108, 76, 52, 161, 104, 145, 248, 78, 123]