duanna5749 2015-04-29 08:05
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Golang正则表达式:[]字符串的FindAllStringSubmatch

I download a multiline file from Amazon S3 in format like:

ColumnAv1 ColumnBv1 ColumnCv1 ...
ColumnAv2 ColumnBv2 ColumnCv2 ...

the file is of type byte. Then I want to parse this with regex:

matches := re.FindAllSubmatch(file,-1)

then I want to feed result row by row to function which takes []string as input (string[0] is ColumnAv1, string[1] is ColumnBv2, ...).

How should I convert result of [][][]byte to []string containing first, second, etc row? I suppose I should do it in a loop, but I cannot get this working:

for i:=0;i<len(len(matches);i++{
    tmp:=myfunction(???)
}

BTW, Why does function FindAllSubmatch return [][][]byte whereas FindAllStringSubmatch return [][]string?

(Sorry I don't have right now access to my real example, so the syntax may not be proper)

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  • dqy006150 2015-04-29 08:30
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    It's all explained extensively in the package's documentation.
    Read the parapgraph which explains :

    There are 16 methods of Regexp that match a regular expression and identify the matched text. Their names are matched by this regular expression:

    Find(All)?(String)?(Submatch)?(Index)?

    In your case, you probably want to use FindAllStringSubmatch.


    In Go, a string is just a read-only []byte.
    You can choose to either keep passing []byte variables around,
    or cast the []byte values to string :

    var byteSlice = []byte{'F','o','o'}
    var str string
    
    str = string(byteSlice)
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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