Golang正则表达式：[]字符串的FindAllStringSubmatch

Question

I download a multiline file from Amazon S3 in format like:

ColumnAv1 ColumnBv1 ColumnCv1 ...
ColumnAv2 ColumnBv2 ColumnCv2 ...

the file is of type byte. Then I want to parse this with regex:

matches := re.FindAllSubmatch(file,-1)

then I want to feed result row by row to function which takes []string as input (string[0] is ColumnAv1, string[1] is ColumnBv2, ...).

How should I convert result of [][][]byte to []string containing first, second, etc row? I suppose I should do it in a loop, but I cannot get this working:

for i:=0;i<len(len(matches);i++{
    tmp:=myfunction(???)
}

BTW, Why does function FindAllSubmatch return [][][]byte whereas FindAllStringSubmatch return [][]string?

(Sorry I don't have right now access to my real example, so the syntax may not be proper)

Answer 1

It's all explained extensively in the package's documentation.
Read the parapgraph which explains :

There are 16 methods of Regexp that match a regular expression and identify the matched text. Their names are matched by this regular expression:

Find(All)?(String)?(Submatch)?(Index)?

In your case, you probably want to use FindAllStringSubmatch.

---

In Go, a string is just a read-only []byte.
You can choose to either keep passing []byte variables around,
or cast the []byte values to string :

var byteSlice = []byte{'F','o','o'}
var str string

str = string(byteSlice)