I'm a bit new to Go, but I'm trying to replace every nth instance of my string with a comma. So for example, a part of my data looks as follows:
"2017-06-01T09:15:00+0530",1634.05,1635.95,1632.25,1632.25,769,"2017-06-01T09:16:00+0530",1632.25,1634.9,1631.65,1633.5,506,"2017-06-01T09:17:00+0530",1633.5,1639.95,1633.5,1638.4,991,
I want to replace every 6th comma
with a '
'
so it looks like
"2017-06-01T09:15:00+0530",1634.05,1635.95,1632.25,1632.25,769"
"2017-06-01T09:16:00+0530",1632.25,1634.9,1631.65,1633.5,506"
"2017-06-01T09:17:00+0530",1633.5,1639.95,1633.5,1638.4,991"
I've looked at the regexp
package and that just seems to be a finder. The strings
package does have a replace but I don't know how to use it to replace specific indices. I also don't know how to find specific indices without going through the entire string character by character. I was wondering if there is a regEx solution that is more elegant than me writing a helper function.
Strings are immutable so I'm not able to edit them in place.
EDIT: Cast the string into []bytes. This allows me to edit the string in place. Then the rest is a fairly simple for loop, where dat
is the data.