douyu5775 2019-09-16 11:00
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如何解压缩单个文件?

I've found lots of examples on how to extract all files from .zip, but I can't figure out how to extract a single file without iterating over all files in the .zip file.

Is it possible in Go to extract a single file from a .zip archive without iterating over all files in the .zip file?

For example, if a zip file contained:

folder1/file1.txt
folder1/file2.txt
folder1/file3.txt
folder2/file1.txt

How would I extract only folder2/file1.txt?

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  • dongmeiyi2266 2019-09-16 12:23
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    zip.Reader provides you the content of the archive, the files as a slice (of zip.File). There is no helper method to get a file by name, you have to iterate over the files with a loop. You don't need to open / extract the files, but to find a file by name, you have to use a loop.

    For example:

    r, err := zip.OpenReader("testdata/readme.zip")
    if err != nil {
        log.Fatal(err)
    }
    defer r.Close()
    
    for _, f := range r.File {
        if f.Name != "folder2/file1.txt" {
            continue
        }
    
        // Found it, print its content to terminal:
        rc, err := f.Open()
        if err != nil {
            log.Fatal(err)
        }
        _, err = io.Copy(os.Stdout, rc)
        if err != nil {
            log.Fatal(err)
        }
        rc.Close()
        fmt.Println()
        break
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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