duandi8613 2016-08-31 02:47 采纳率: 100%
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为什么断言时会出现“无法分配”错误?

req is a interface{} and PostAccountRequest,CreateAccountRequest is struct, when I do this, I get cannot assign *account.PostAccountRequest to v (type *account.CreateAccountRequest) in multiple assignment

v, ok := req.(*account.CreateAccountRequest)                                                         
if ok {
    if v, ok = req.(*account.PostAccountRequest); ok {
        panic(ok)
    }
}
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  • dqbh8054 2016-08-31 02:54
    关注

    The snippet of code defines one variable v with type *account.CreateAccountRequest. The second type assertion attempts to assign a *account.PostAccountRequest to the variable v. This is an error.

    The code will compile if you create a second variable v:

    v, ok := req.(*account.CreateAccountRequest)                                                         
    if ok {
        if v, ok := req.(*account.PostAccountRequest); ok { // note ":"
          panic(ok)
      }
    }
    

    ... but does not make sense because v can only be one of the struct types.

    Perhaps you are looking for something like this:

    var name, token string
    switch v := v.(type) {
    case *account.CreateAccountRequest:
     // v is a *account.CreateAccountRequest in this branch of the switch
     name = v.Name
     token = v.Token
    case *account.PostAccountRequest:
     // v is a *account.PostAccountRequest in this branch of the switch
     name = v.Name
     token = v.Token
    default:
     // panic?
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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