dsuvs66406
dsuvs66406
2019-02-11 11:08

成对迭代字符串数组以创建映射[重复]

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I have an array of strings whose length is always a multiple of two.

I want to create a map out of this array, so that

myarr = ["key1", "val1", "key2", "val2", ...]

becomes a map where

mymap := mapify(myarr)
mymap['key1'] == "val1"
mymap['key2'] == "val2"

In Python I can do this with the following code

mymap = {}
for x, y in zip(*[iter(myarr)]*2):
  mymap[x] = y
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1条回答

  • doudouba4520 doudouba4520 2年前

    You can write your own function, something like that:

    package main
    
    import (
        "fmt"
    )
    
    var myarr = []string{"key1", "val1", "key2", "val2"}
    
    func mapify(kv []string) map[string]string {
        mymap := make(map[string]string)
    
        for i := 0; i+1 <= len(kv); i = i + 2 {
            mymap[kv[i]] = kv[i+1]
        }
    
        return mymap
    }
    
    func main() {
        fmt.Println(myarr)
        fmt.Println(mapify(myarr))
    }
    

    Outputs

    [key1 val1 key2 val2]
    map[key1:val1 key2:val2]
    

    Try it here

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