如何将变量作为外壳脚本文件运行

Question

I need to run a variable as shell script file in golang. I tried like below code

package main

import (
    "fmt"
    "os/exec"
)

func main() {
   var namespaceYaml string = `#!/bin/bash
docker verson`

   out, err := exec.Command(namespaceYaml).Output()
   fmt.Println(err, string(out))
}

But I cannot get any result. I cannot find where is the mistake.

Please anyone to fix this issue. Thanks in advance.

Answer 1

From official doc:

func Command(name string, arg ...string) *Cmd

Command returns the Cmd struct to execute the named program with the given arguments.

Try this:

package main

import (
    "fmt"
    "os/exec"
)

func main() {
    out, err := exec.Command("docker", "version").Output()
    if err != nil {
        log.Fatal(err)
    }
    fmt.Printf("Docker version is: %s
", out)
}

Useful links for further details:

• exec
• examples

Note: make sure docker is installed on your machine.