怎么用python画出随机个数，随机高度，随机宽度而不重复的矩形？

Question

如题，最好能用递推式，我用if函数没做下去，请问能有大佬帮忙看看吗

Answer 1

import turtle
import random

# 设置画布大小
turtle.setup(800, 600)

# 随机生成矩形个数
num_rectangles = random.randint(5, 10)

# 定义矩形宽度和高度的范围
min_width = 20
max_width = 100
min_height = 20
max_height = 100

# 定义已经绘制的矩形的位置和大小
rectangles = []

# 定义绘制矩形的函数
def draw_rectangle(x, y, width, height):
    turtle.penup()
    turtle.goto(x, y)
    turtle.pendown()
    turtle.setheading(0)
    turtle.forward(width)
    turtle.right(90)
    turtle.forward(height)
    turtle.right(90)
    turtle.forward(width)
    turtle.right(90)
    turtle.forward(height)

# 循环绘制矩形
for i in range(num_rectangles):
    # 随机生成矩形的宽度和高度
    width = random.randint(min_width, max_width)
    height = random.randint(min_height, max_height)

    # 随机生成矩形的位置，直到不与已经绘制的矩形重叠
    while True:
        x = random.randint(-350, 350)
        y = random.randint(-250, 250)
        overlap = False
        for rect in rectangles:
            if x < rect[0] + rect[2] and x + width > rect[0] and y < rect[1] + rect[3] and y + height > rect[1]:
                overlap = True
                break
        if not overlap:
            break

    # 绘制矩形
    draw_rectangle(x, y, width, height)

    # 将已经绘制的矩形的位置和大小添加到列表中
    rectangles.append((x, y, width, height))

# 隐藏画笔
turtle.hideturtle()

# 显示绘制结果
turtle.done()