dongzhan1492 2018-07-29 07:16
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函数列表中的Golang函数具有最后一个值

In the following snippet I create a func list that should, the way I see it, contain funcs that print the numbers 0 1 2.

package main

import "fmt"

func main() {
    flist := make([]func(), 0)
    for i := 0; i < 3; i++ {
        flist = append(flist, func() { fmt.Printf("%d ", i) })
    }
    for j := 0; j < 3; j++ {
        flist[j]()
    }
}

However, all funcs in flist are the same main.main.func1 and the output is

3 3 3

even though i never reaches the value 3 in the loop. This would make me thing the func is simply taking the address of i, creating the same func every time but that i is out of scope when the funcs are called later.

What am I missing here?

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1条回答 默认 最新

  • doupuzhimuhan9216 2018-07-29 07:25
    关注

    If we think of what code is generated for those functions, it is identical indeed: the same variable is used every time. Even though i is out of scope after the loop, it becomes the part of the closures and its latest value is seen by the function when they run. By the moment the loop exits, it's 3. If you want to bind a closure to the particular value and guard it from further changes, you may create a narrow-scoped variable, like this:

    package main
    
    import "fmt"
    
    func main() {
        flist := make([]func(), 0)
        for i := 0; i < 3; i++ {
            j := i  // a different variable for each iteration
            flist = append(flist, func() { fmt.Printf("%d ", j) })
        }
        for j := 0; j < 3; j++ {
            flist[j]()
        }
    } 
    
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