douzhen5158 2017-01-26 12:32
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如何从xml的根元素获取第一级注释

my xsd file has following structure:

<?xml version="1.0" encoding="UTF-8"?>
<!-- EIS docs-ws-api Integration Scheme, version 6.4, create date 15.11.2016 -->
<someTag></someTag>

how to get this comment? i try did it on playground https://play.golang.org/p/PVHux_Gvb7

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  • dsfhd78978 2017-01-26 19:19
    关注

    As mentioned in other answer, xml.Unmarshal can parse comment only if it's part of XML element.

    External library xmlpath which implements XPath specification can be useful in your case.

    Install: go get gopkg.in/xmlpath.v1

    Let's extract preceding comment of tag named someTag from your example xml.

    import (
        "fmt"
        "log"
    
        "strings"
    
        xmlpath "gopkg.in/xmlpath.v1"
    )
    
    func main() {
        data := `
    <?xml version="1.0" encoding="UTF-8"?>
    <!-- EIS docs-ws-api Integration Scheme, version 6.4, create date 15.11.2016 -->
    <someTag></someTag>
    `
        path := xmlpath.MustCompile("/someTag/preceding::comment()")
        root, err := xmlpath.Parse(strings.NewReader(data))
        if err != nil {
            log.Fatal(err)
        }
        if comment, ok := path.String(root); ok {
            fmt.Println(comment)
        }
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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