将golang deepEqual接口{}转换为整数

Question

I'm using the redigo redis library, and checking if a key is already present in a redis set. I'm using the redis command SISMEMBER via the redigo's Do method which returns an interface. It is the response of the command being executed using Do. In case of SISMEMBER command, the response in a 1 or 0. and in this particular case, the response is 0 as the given key is not present in this set. however reflect.DeepEqual(resp, 0) is returning false when true is expected. Is this not the correct way to use DeepEqual function?

import (
    "fmt"
    "reflect"

    "github.com/garyburd/redigo/redis"
)

func main() {
    conn, err := redis.Dial("tcp", "127.0.0.1:6379")
    if err != nil {
        fmt.Println(err.Error())
        return
    }
    defer conn.Close()

    resp, err := conn.Do("SISMEMBER", "mySet", "Hello")
    if reflect.DeepEqual(resp, 0) {
        fmt.Println("record doesn't exist")
    }

}

Answer 1

Instead of over complicate your code, you can use some build-in functions of redigo to convert the response to int and afterward check if the key is or is not in redis.

resp, err := redis.Int(conn.Do("SISMEMBER", "mySet", "Hello"))
if err != nil {
    // some error handler
}
if resp == 0 {
    fmt.Println("record doesn't exist")
}