如何在Go中将接口{}的切片转换为结构类型的切片？ [重复]

Question

This question already has an answer here:

• Type converting slices of interfaces 5 answers

func GetFromDB(tableName string, m *bson.M) interface{} {
    var (
        __session *mgo.Session = getSession()
    )

    //if the query arg is nil. give it the null query
    if m == nil {
        m = &bson.M{}
    }

    __result := []interface{}{}
    __cs_Group := __session.DB(T_dbName).C(tableName)
    __cs_Group.Find(m).All(&__result)

    return __result
}

call

GetFromDB(T_cs_GroupName, &bson.M{"Name": "Alex"}).([]CS_Group)

runtime will give me panic:

panic: interface conversion: interface is []interface {}, not []mydbs.CS_Group

how convert the return value to my struct?

</div>

Answer 1

You need to convert the entire hierarchy of objects:

rawResult := GetFromDB(T_cs_GroupName, &bson.M{"Name": "Alex"}).([]interface{})
var result []CS_Group
for _, m := range rawResult {
   result = append(result, 
       CS_Group{
         SomeField: m["somefield"].(typeOfSomeField),
         AnotherField: m["anotherfield"].(typeOfAnotherField),
       })
}

This code is for the simple case where the type returned from mgo matches the type of your struct fields. You may need to sprinkle in some type conversions and type switches on the bson.M value types.

An alternate approach is to take advantage of mgo's decoder by passing the output slice as an argument:

func GetFromDB(tableName string, m *bson.M, result interface{}) error {
    var (
        __session *mgo.Session = getSession()
    )
    //if the query arg is nil. give it the null query
    if m == nil {
        m = &bson.M{}
    }
    __result := []interface{}{}
    __cs_Group := __session.DB(T_dbName).C(tableName)
    return __cs_Group.Find(m).All(result)
}

With this change, you can fetch directly to your type:

 var result []CS_Group
 err := GetFromDB(T_cs_GroupName, bson.M{"Name": "Alex"}, &result)

See also: FAQ: Can I convert a []T to an []interface{}?