如何在Go中将方法作为参数传递？

Question

i just want to pass some methods that they belongs to 'any' struct to their receiver method.

These are prototype methods.

func (r *Rules) Checker(fn ...func()) {}
func (r *Rules) CheckEmpty() {}
func (r *Rules) CheckMax()  {}

and what i want is here:

v.Rule.Checker(
    v.Rule.CheckEmpty(),
    v.Rule.CheckMax(),
)

But i think function types are not equal and the program giving me error 'type void type as type func()'. Is there a way to call these methods as i wanted to ?

Answer 1

You want to pass the function itself to Checker, and not the result of the function call. To do that, drop the () after the function name so the function is not being called:

v.Rule.Checker(
    v.Rule.CheckEmpty,
    v.Rule.CheckMax,
)