dsigh7478
2019-08-15 13:32
浏览 111
已采纳

如何在Go中将方法作为参数传递?

i just want to pass some methods that they belongs to 'any' struct to their receiver method.

These are prototype methods.

func (r *Rules) Checker(fn ...func()) {}
func (r *Rules) CheckEmpty() {}
func (r *Rules) CheckMax()  {}

and what i want is here:

v.Rule.Checker(
    v.Rule.CheckEmpty(),
    v.Rule.CheckMax(),
)

But i think function types are not equal and the program giving me error 'type void type as type func()'. Is there a way to call these methods as i wanted to ?

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我只想将属于“ any”结构的某些方法传递给接收方方法。

这些是原型方法。

  func(r * Rules)Checker(fn ... func(  )){} 
func(r *规则)CheckEmpty(){} 
func(r *规则)CheckMax(){} 
   
 
 

,我想要的是 此处:

  v.Rule.Checker(
 v.Rule.CheckEmpty(),
 v.Rule.CheckMax(  ),
)
   
 
 

但是我认为函数类型不相等,并且程序给我错误'类型无效类型为func()类型'。 一种我想调用的方法的方法?

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1条回答 默认 最新

  • dsgm5631 2019-08-15 13:35
    已采纳

    You want to pass the function itself to Checker, and not the result of the function call. To do that, drop the () after the function name so the function is not being called:

    v.Rule.Checker(
        v.Rule.CheckEmpty,
        v.Rule.CheckMax,
    )
    
    已采纳该答案
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