在golang中，如何保护自己的锁安全装置不受调用者破坏？

Question

I try use "sync.mutex" protect my func,but i found that the lock still uses the caller to destroy it.

var mutex sync.mutex

This is error:

//caller use
func a() {
    for i := 0; i < 10; i++ {
        go b(i)
    }
}

//My func
func b(i int) {
    mutex.Lock()
    fmt.Println(i)
    mutex.Unlock()
}

this is success,but destroyed my encapsulation method:

//caller use
func a() {
    for i := 0; i < 10; i++ {
        mutex.Lock()
        go b(i)
    }
}

//my func
func b(i int) {
    fmt.Println(i)
    mutex.Unlock()
}

Thanks

Answer 1

The Go Programming Language Specification

Exported identifiers

An identifier may be exported to permit access to it from another package. An identifier is exported if both:

• the first character of the identifier's name is a Unicode upper case letter (Unicode class "Lu"); and
• the identifier is declared in the package block or it is a field name or method name.

All other identifiers are not exported.

Put the function in its own package and don't export the mutex. For example.

package b

import (
    "fmt"
    "sync"
)

var mutex sync.Mutex

func B(i int) {
    mutex.Lock()
    fmt.Println(i)
    mutex.Unlock()
}

To use,

package a

import "b"

func a() {
    for i := 0; i < 10; i++ {
        go b.B(i)
    }
}