2014-02-07 07:16

# 整数的映射-> Go中的2d slice

I want to have a map of integers to slices with different dimensions.

``````var SIZE_TO_PERM = make(map[int][][]uint32, 3)

var THREE_C_THREE = [...][3]int {
{0, 1, 2},
}

var FOUR_C_THREE = [...][3]int {
{0, 1, 2}, {0, 1, 3}, {0, 3, 2}, {3, 1, 2},
}

var FIVE_C_THREE = [...][3]int {
// ... etc
}

func init() {
SIZE_TO_PERM = map[int][][]uint32 {
3 : THREE_C_THREE,
4 : FOUR_C_THREE,
5 : FIVE_C_THREE,
}
}
``````

But this doesn't work, as Go throws errors:

``````# command-line-arguments
./test.go:96: cannot use THREE_C_THREE (type [1][5]int) as type [][]uint32 in map value
./test.go:97: cannot use FOUR_C_THREE (type [4][5]int) as type [][]uint32 in map value
./test.go:98: cannot use FIVE_C_THREE (type [20][5]int) as type [][]uint32 in map value
``````

How can I get around this? Perhaps I could somehow have Go map an int to a pointer/reference to a map? Then all the types would be the same, I'd just have to follow the address to get the map there. The problem is I wouldn't know apriori which type I'd find there...

All new to Go, so any tips appreciated.

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#### 1条回答

• dongmou9260 7年前

First of all, there is a difference between a slice and an array.

``````var a [3]int // Array of 3 ints
var s []int // Slice of ints
``````

In your case, the map can store slices, but the data is stored in different types of arrays.

The size of an array is part of its type. And because of Go's strict typing, you cannot set a value of one array type/size to a value of a different array type/size.

Instead we have slices. Slices uses an underlying array, but may differ in length and capacity.

``````var THREE_C_THREE = [][]uint32 { // Changed type from [1][3]int to [][]uint32
{0, 1, 2},
}

var FOUR_C_THREE = [][]uint32 { // Changed type from [4][3]int to [][]uint32
{0, 1, 2}, {0, 1, 3}, {0, 3, 2}, {3, 1, 2},
}

var FIVE_C_THREE = [][]uint32 { // Changed type from [5][3]int to [][]uint32
// ... etc
}
``````