如何休息时间睡眠

Question

I just started picking up Golang a couple days ago and I can't seem to figure out to break out of time.Sleep()...

I can return / break out of the for loop, but the function wont return since Sleep continues doing its thing.

I am guessing the solution is pretty simple, but I can't seem to find the answer.

func main() {
  ticker := time.NewTicker(time.Second * 1)

  go func() {
    for i := range ticker.C {
      fmt.Println("tick", i)
      ticker.Stop()
      break
    }
  }()
  time.Sleep(time.Second * 10)
      ticker.Stop()

  fmt.Println("Hello, playground")
}

Thanks in advance!

Answer 1

It sounds like you want to send the main goroutine a message telling it your other goroutine is complete. For that, channels are the best way to go.

func main() {
    ticker := time.NewTicker(time.Second)
    done := make(chan bool, 1)

    go func() {
        for i := range ticker.C {
            fmt.Println("tick", i)
            ticker.Stop()
            break
        }

        done <- true
    }()

    timer := time.NewTimer(time.Second/2)
    select {
    case <-done:
        timer.Stop()
    case <-timer.C:
        ticker.Stop()
    }

    fmt.Println("Done")
}

Working example at http://play.golang.org/p/5NFsvC5f7P

When the timer is greater than ticker, it ticks. When it is less than, all you see is "done".