douzhou7037 2018-12-31 10:21
浏览 241
已采纳

读取和解析大型XML文件的性能问题

I have a directory which contains several large XML files (total size is about 10 GB). Is there any way to iterate through the directory containing the XML files and read 50 byte by 50 byte and parse the XML files with high performance?

func (mdc *Mdc) Loadxml(path string, wg sync.WaitGroup) {
    defer wg.Done()
    //var conf configuration
    file, err := os.Open(path)
    if err != nil {
        log.Fatal(err)
    }
    defer file.Close()
    scanner := bufio.NewScanner(file)
    buf := make([]byte, 1024*1024)
    scanner.Buffer(buf, 50)
    for scanner.Scan() {
        _, err := file.Read(buf)
        if err != nil {
            log.Fatal(err)
        }
    }

    err = xml.Unmarshal(buf, &mdc)
    if err != nil {
        log.Fatal(err)
    }
    fmt.Println(mdc)
}
  • 写回答

2条回答 默认 最新

  • douhuan1257 2018-12-31 12:08
    关注

    You can do something even better: You can tokenize your xml files.

    Say you have an xml like this

    <inventory>
      <item name="ACME Unobtainium">
        <tag>Foo</tag>
        <count>1</count>
      </item>
      <item name="Dirt">
        <tag>Bar</tag>
        <count>0</count>
      </item>
    </inventory>
    

    you can actually have the following data model

    type Inventory struct {
        Items []Item `xml:"item"`
    }
    
    type Item struct {
        Name  string   `xml:"name,attr"`
        Tags  []string `xml:"tag"`
        Count int      `xml:"count"`
    }
    

    Now, all you have to do is to use filepath.Walk and do something like this for each file you want to process:

        decoder := xml.NewDecoder(file)
    
        for {
            // Read tokens from the XML document in a stream.
            t, err := decoder.Token()
    
            // If we are at the end of the file, we are done
            if err == io.EOF {
                log.Println("The end")
                break
            } else if err != nil {
                log.Fatalf("Error decoding token: %s", err)
            } else if t == nil {
                break
            }
    
            // Here, we inspect the token
            switch se := t.(type) {
    
            // We have the start of an element.
            // However, we have the complete token in t
            case xml.StartElement:
                switch se.Name.Local {
    
                // Found an item, so we process it
                case "item":
                    var item Item
    
                    // We decode the element into our data model...
                    if err = decoder.DecodeElement(&item, &se); err != nil {
                        log.Fatalf("Error decoding item: %s", err)
                    }
    
                    // And use it for whatever we want to
                    log.Printf("'%s' in stock: %d", item.Name, item.Count)
    
                    if len(item.Tags) > 0 {
                        log.Println("Tags")
                        for _, tag := range item.Tags {
                            log.Printf("\t%s", tag)
                        }
                    }
                }
            }
        }
    

    Working example with dummy XML: https://play.golang.org/p/MiLej7ih9Jt

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 乌班图ip地址配置及远程SSH
  • ¥15 怎么让点阵屏显示静态爱心,用keiluVision5写出让点阵屏显示静态爱心的代码,越快越好
  • ¥15 PSPICE制作一个加法器
  • ¥15 javaweb项目无法正常跳转
  • ¥15 VMBox虚拟机无法访问
  • ¥15 skd显示找不到头文件
  • ¥15 机器视觉中图片中长度与真实长度的关系
  • ¥15 fastreport table 怎么只让每页的最下面和最顶部有横线
  • ¥15 R语言卸载之后无法重装,显示电脑存在下载某些较大二进制文件行为,怎么办
  • ¥15 java 的protected权限 ,问题在注释里