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2017-03-23 04:25
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Golang Gin-Gonic将路线拆分为多个文件[重复]

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I am looking to split my routes.go into multiple files so that each group is in its own package. Can someone point me to an example of some code where someone has done this with Gin?

i.e.

package auth
...
auth = route.Group("/auth"){
    auth.GET(...
    auth.POST(...
}
...

package users
...
user = route.Group("/user"){
    user.GET(...
    user.POST(...
}
...

package main
import (
     "auth"
     "users"
)
...
router = gin.Default()
router.Register(auth.auth, users.user)
router.Run()
...
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  • golang gin-gonic并拆分文件包 1个答案

    我希望将route.go拆分为多个文件,以便每个文件 组在自己的程序包中。 有人可以给我指出一些用Gin完成此操作的代码示例吗?

     程序包auth 
     ... 
    auth = route.Group(“ / auth”){
     auth.GET(... 
     auth.POST(。  .. 
    } 
     ... 
     
    包用户
     ... 
    user = route.Group(“ / user”){
     user.GET(... 
     user.POST(..  。
    } 
     ... 
     
    包main 
    import(
    “ auth” 
    “ users” 
    )
     ... 
    router = gin.Default()
    router.Register(auth。  auth,users.user)
    router.Run()
     ... 
       
     
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1条回答 默认 最新

  • doufei4418 2017-03-23 05:34
    已采纳

    The way to do this is to create a function in each that takes a route as a parameter, and then adds the routes to the parameter:

    package auth
    import "...gin"
    func Routes(route *gin.Engine)
    auth := route.Group("/auth"){
        auth.GET(...
        auth.POST(...
    }
    ...
    
    package users
    import "...gin"
    func Routes(route *gin.Engine)
    user := route.Group("/user"){
        user.GET(...
        user.POST(...
    }
    ...
    
    package main
    import (
         "github.com/username/package/sub/auth"
         "github.com/username/package/sub/users"
         "github.com/gin-gonic/gin"
    )
    ...
    router := gin.Default()
    auth.Routes(router) //Added all auth routes
    user.Routes(router) //Added all user routes
    router.Run()
    ...
    
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