doufan1899
doufan1899
采纳率100%
2017-06-02 02:30 阅读 86
已采纳

为什么Golang结构数组无法分配给接口数组

I'm trying to achieve something as below.

package main

import (
    "fmt"
)

type MyStruct struct {
    Value int
}

func main() {
    x := []MyStruct{
        MyStruct{
            Value : 5,
        },
        MyStruct{
            Value : 6,
        },
    }
    var y []interface{}
    y = x // This throws a compile time error

    _,_ = x,y
}

This gives a compile time error:

sample.go:21: cannot use x (type []MyStruct) as type []interface {} in assignment

Why is this not possible?.If not is there any other way to hold generic object arrays in Golang?

  • 点赞
  • 写回答
  • 关注问题
  • 收藏
  • 复制链接分享

1条回答 默认 最新

  • 已采纳
    douan7529 douan7529 2017-06-02 08:14

    interface{} is stored as a two word pair, one word describing the underlying type information and one word describing the data within that interface:

    enter image description here

    https://research.swtch.com/interfaces

    Here we see the first word stores the type information and the second the data within b.

    Struct types are stored differently, they do not have this pairing. Their fields of a struct are laid out next to one another in memory.

    enter image description here

    https://research.swtch.com/godata

    You cannot convert one to the other because they do not have the same representation in memory.

    It is necessary to copy the elements individually to the destination slice.

    https://golang.org/doc/faq#convert_slice_of_interface

    To answer your last question, you could have []interface which is a slice of interfaces, where each interface is represented as above, or just interface{} where the underlying type held in that interface is []MyStruct

    var y interface{}
    y = x 
    

    or

    y := make([]interface{}, len(x))
    for i, v := range x {
        y[i] = v
    }
    
    点赞 评论 复制链接分享

相关推荐