douzhi2988 2017-03-07 21:53
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无法在strconv.ParseFloat问题的参数中使用([[byte]类型)作为类型字符串

pi@raspberrypi:~/Desktop/go $ go run shell1.go

As result i am getting:

pi@raspberrypi:~/Desktop/go $ go run shell1.go
# command-line-arguments
./shell1.go:29: undefined: n
./shell1.go:29: cannot use b (type []byte) as type string in argument to strconv.ParseFloat
./shell1.go:32: undefined: n

Go file (shell1.go) code is:

package main

import (
    //    "net/http"
    //    "github.com/julienschmidt/httprouter"
    "fmt"
    "log"
    "os/exec"
    "strconv"
    "time"
    //"bytes"
    //"encoding/binary"
)
import _ "github.com/go-sql-driver/mysql"
import _ "database/sql"

func main() {
    for {
        time.Sleep(10 * time.Millisecond)
        cmd := exec.Command("gpio.bash")

        b, err := cmd.Output()
        if err != nil {
            log.Fatal(err)
        }
        n, _ = strconv.ParseFloat(b, 10)
        fmt.Println(string(b))
        break
    }

    fmt.Println("Button pressed!!! ", n)

}

Content of (gpio.bash) file is just one command to read gpio

 #!/bin/bash
gpio read 29
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1条回答 默认 最新

  • dongxun1978 2017-03-08 03:34
    关注

    You are working with a command here, which can of course execute just about anything.

    The function is purposely generic, as the true return type varies depending on what you executed. Thus, when you call the output method, you are given a slice of bytes (very generic!). Here is its signature:

    func (c *Cmd) Output() ([]byte, error)
    

    If you know that the bytes will always be a string, then you simply have to do a type conversion to a string:

    n, _ := strconv.ParseFloat(string(b), 10)
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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