显示巨大的十六进制字符串的基数10表示？

Question

Trying to find how to have this hexa string "58068906d6194c6cbda7a6df" into it's base 10 representation.

I tried with this:

i, err := strconv.Parse("58068906d6194c6cbda7a6df", 16, 64)

Obviously I'm getting this error: parsing "58068906d6194c6cbda7a6df"; value out of range

I also need to take the base 10 string representation and get this hexa value back after some processing. i.e.:

base10 := "58068906d6194c6cbda7a6df" => to base 10 string some processing hexa := base10 => to base 16 string

Can I use the fmt package to dislpay the base 10? I know that displaying the hexa of a base 10 I could use %x, but what can I do with an existing string?

Thanks for your help, for a reason I cannot understand, I'm unable to find any way to do this.

Answer 1

Your hex value is larger than int64 can hold, so you have to use a big.Int

https://play.golang.org/p/OPPL43u6nB

i := new(big.Int)
i.SetString("58068906d6194c6cbda7a6df", 16)
fmt.Println(i)

To get a hex string representation from a big.Int, you can use the Text method:

hex := i.Text(16)