编程介的小学生 2020-01-16 11:47 采纳率: 20.5%
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Simulation? 模拟的问题

Problem Description
A computer simulation, a computer model, or a computational model is a computer program, or network of computers, that attempts to simulate an abstract model of a particular system. Computer simulations have become a useful part of mathematical modeling of many natural systems in physics, astrophysics, chemistry and biology, human systems in economics, psychology, social science, and engineering, of course, also computer.
“Fundamentals of compiling” is an important course for computer science students. In this course, most of us are asked to write a compiler to simulate how a programming language executes. Today, boring iSea invites a new programming language, whose name is Abnormal Cute Micro (ACM) language, and, YOU are assigned the task to write a compiler for it.
ACM language only contains two kinds of variables and a few kinds of operations or functions, and here are some BNF-like rules for ACM.

Also, here is some explanation for these rules:
1) In ACM expressions, use exactly one blank to separate variables and operators, and as the rule indicates, the operator should apply right to left, for example, the result of “1 - 2 - 3" should be 2.
2) In the build function, use exactly one blank to separate integers, too.
3) Beside there are brackets in function, no other bracket exists.
4) All the variables are conformable, and never exceed 10000.
Given an ACM expression, your task is output its value. If the result is a integer, just report it, otherwise report an array using the format “{integer_0, integer_1, … , integer_n}”.

Input
The first line contains a single integer T, indicating the number of test cases.
Each test case includes a string indicating an valid ACM expression you have to process.

Technical Specification
1. 1 <= T <= 100
2. 1 <= |S| <= 100, |S| indicating the length of the string.

Output
For each test case, output the case number first, then the result variable.

Sample Input
10
1 + 1
1 - 2 - 3
dance(3)
vary(2) * 2
vary(sum(dance(5) - 1))
dance(dance(-3))
1 - 2 - 3 * vary(dull(build(1 2 3)))
dance(dance(dance(dance(dance(2)))))
sum(vary(100)) - sum(build(3038))
build(sum(vary(2)) dull(build(1 0)) 2 dull(dance(2))) - build(1 1 1 1)

Sample Output
Case 1: 2
Case 2: 2
Case 3: {3, -2, 1}
Case 4: {2, 4}
Case 5: {2, 1}
Case 6: -4
Case 7: {2, 5}
Case 8: {4, -3, 2, -1}
Case 9: 2012
Case 10: {2, 0, 1, 2}

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