求各位大佬帮忙，PAT1031 查验身份证

Question

大佬能不能帮我看看为什么这个答案输出总是循环的一个身份证，而不是多个有问题的身份证？

#include<cstdio>
#include<cstring>
char find[15] = {'1','0','X','9','8','7','6','5','4','3','2'} ;
int power[20] = {7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2};
int main()
{
    int n;
    int result = 0;
    int number = 0;
    char str[20];
    char * wrong[20];
    scanf("%d", &n);
    for(int j = 0; j < n; j++)
    {
        int i = 0;
        scanf("%s", str);
        for(i = 0; i < 17; i++)
        if(str[i] >= '0' && str[i] <= '9')
        result += (str[i]-'0')*power[i];
        else
        break;

        if(i < 17)
        wrong[number++] = str;
        else if(find[result % 11] != str[17])
        wrong[number++] = str;
    }
    if(number == 0)
    printf("All passed\n");
    else
    {
        for(int j = 0; j < number; j++)
        printf("%s\n", wrong[j]);
    }

    return 0;
}

Answer 1

问题解决的话，请点下采纳

// Q1052502.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"


#include<cstdio>
#include<cstring>
#include<stdlib.h>
char find[15] = {'1','0','X','9','8','7','6','5','4','3','2'} ;
int power[20] = {7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2};
int main()
{
    int n;
    int result = 0;
    int number = 0;
    char str[20];
    char * wrong[20];
    for (int i = 0; i < 20; i++)
        wrong[i] = (char *)malloc(sizeof(char) * 100);
    scanf("%d", &n);
    for(int j = 0; j < n; j++)
    {
        int i = 0;
        scanf("%s", str);
        for(i = 0; i < 17; i++)
        if(str[i] >= '0' && str[i] <= '9')
        result += (str[i]-'0')*power[i];
        else
        break;

        if(i < 17)
        strcpy(wrong[number++], str);
        else if(find[result % 11] != str[17])
        strcpy(wrong[number++], str);
    }
    if(number == 0)
    printf("All passed\n");
    else
    {
        for(int j = 0; j < number; j++)
        printf("%s\n", wrong[j]);
    }

    return 0;
}