大佬,一组数里面是0,0,0,1,0,0,2,2,0,2,2,0,0,3,0,0,0,0 (0,2,2,0,2,2就算一个室早三联)如果022022是连续出现的话也只算一个比如022022022022这样也只算一个不连续的022022才++,统计022022的个数,求大佬帮忙
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- Okay6 2020-03-02 18:04关注
package com.lee.study; import java.util.regex.Matcher; import java.util.regex.Pattern; public class Study20 { public static int getAmount(int[] numbers) { Pattern p = Pattern.compile("(?<!022022)022022(?!022022)"); StringBuilder stringBuilder = new StringBuilder(numbers.length); for (int number : numbers) { stringBuilder.append(number); } Matcher m = p.matcher(stringBuilder.toString()); int counter = 0; while (m.find()) { counter++; } return counter; } public static void main(String[] args) { int[] numbers = {0, 0, 0, 1, 0, 0, 2, 2, 0, 2, 2,0, 2, 2, 0, 2, 2, 0, 0, 3, 0, 0, 0, 0}; System.out.println("应该输出1"); System.out.println(getAmount(numbers)); } }
如果采纳,希望给个赞哦!@@
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