高分悬赏:Java语言怎么交换两个双向链表,首先请给出链表的设计类,然后再交换!
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- 大拙男 2020-04-16 10:20关注
public class SLink {
public SNode head;public SLink() { this.head = new SNode(); } public boolean interChangeById(int id1,int id2) { SNode s = head; SNode node1 = null,node2 = null; int node1Count,node2Count; node1Count = node2Count = 0; if(id1 == id2) { return true; } /** * 向下遍历 */ while (s.next != null) { s = s.next; node1Count ++ ; if(s.student.stuId == id1) { /** * 记录节点1 */ node1 = s; break; } } s = head; while (s.next != null) { s = s.next; node2Count ++ ; if(s.student.stuId == id2) { /** * 记录节点2 */ node2 = s; break; } } if(node1 != null && node2 != null) { SNode temp = new SNode(); /** * node1在后 */ if(node1Count > node2Count) { temp.next = node1.next; temp.prev = node1.prev; /** * 记录那个节点就先处理那个节点 * 1、交换next * 2、交换prev * 3、设置之前节点的next(对接) */ node1.next = node2.next; node1.prev = node2.prev; node2.prev.next = node1; if(node1.next.equals(node1)) { /** * 说明两个节点相邻 */ node1.next = node2; node2.next = temp.next; node2.prev = node1; }else { /** * 说明节点不相邻 */ node2.next = temp.next; node2.prev = temp.prev; temp.prev.next = node2; } }else { /** * node1在前 */ temp.next = node2.next; temp.prev = node2.prev; node2.next = node1.next; node2.prev = node1.prev; node1.prev.next = node2; if(node2.next.equals(node2)) { node2.next = node1; node1.next = temp.next; node1.prev = node2; }else { node1.next = temp.next; node1.prev = temp.prev; temp.prev.next = node1; } } return true; } return false; } public void displayStudent() { SNode s = head; while (s.next != null) { s = s.next; System.out.println(s.student); } }
}
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