用scanf读入一句带有空格的英文以"End"结尾，计算出这句话中的单词个数，并且不算End，代码没有输出？

Question

#include
#include
int main()
{
char ch[20];//This string has at most 99 characters and one character for '\0'.
int i=0;//Initialization.

int j;
printf("Please input a line of sentence: \n");//Input the string.
do
{
    scanf("%s",ch);
}
while(strcmp(ch,"End")!='\0');

if((ch[0]>='a'&&ch[0]<='z')||(ch[0]>='A'&&ch[0]<='Z'))//If the first character is a letter, then intialize j=1.
{
    j=1;
}
else//If the first character is not a letter, then intialize j=0.
{
    j=0;
}

for(i=1;i<100;i++)
{
    if(((ch[i]>='a'&&ch[i]<='z')||(ch[i]>='A'&&ch[i]<='Z'))&&(ch[i-1]==' '))//If the ith character is a letter and the previous one is a space.
               {
                    j++;//Then the number of the English words plus one.
               }
    if(ch[i-1]=='E'&&ch[i]=='n'&&ch[i+1]=='d')
    {
        j=j-1;
    }
}


printf("the output is:%d",j);//Output the result: the number of English words in a sentence.
return 0;

}

Answer 1

do
{
scanf("%s",ch);
}
while(strcmp(ch,"End")!='\0');
把上面这段换成以回车结束输入的字符集
scanf("%[^\n]",ch);