如何用Ajax jQuery获取人名？

Question

我正试图通过XML获取一个人的名字。我正在使用jQuery获取并将名称应用于html元素。我之前试过得到人名，但它没有成功应用。是哪里有什么问题吗？我的函数语法是免费的，但我无法理解为什么它不能工作。

$.ajax({
    url: 'http://support.example.com/support/api.asp?token=e6k05nbssjkjqo3qk7rd4rvr01hvlv&cmd=viewPerson',
    datatype: 'xml',
    success: function(data) {
        $(data).find('sFullName').each(function() { 
            var sf = $(this).find('text').text();
           $('span#username').append(
                $('<a />', {
                    text: sf
                })
                );            
        });

    },
    error: function() {
        console.log();
    }
});

Answer 1

For each <sFullName> element you are finding all the <text> elements.

The data you are requesting looks, in part, like this:

<sFullName><![CDATA[Rajat Sharma]]></sFullName>

The element doesn't have any <text> elements as its descendants.

You simply want:

var sf = $(this).text();

---

var data = $.parseXML("<?xml version=\"1.0\" encoding=\"UTF-8\"?><response><person><ixPerson>400</ixPerson><sFullName><![CDATA[Rajat Sharma]]></sFullName><sEmail><![CDATA[[e-mail]]]></sEmail><sPhone></sPhone><fAdministrator>true</fAdministrator><fCommunity>false</fCommunity><fVirtual>false</fVirtual><fDeleted>false</fDeleted><fNotify>true</fNotify><sHomepage></sHomepage><sLocale><![CDATA[en-ca]]></sLocale><sLanguage><![CDATA[en-us]]></sLanguage><sTimeZoneKey><![CDATA[Eastern Standard Time]]></sTimeZoneKey><sSnippetKey><![CDATA[`]]></sSnippetKey><ixBugWorkingOn>0</ixBugWorkingOn><nType>1</nType></person></response>");

$(data).find('sFullName').each(function () {
    var sf = $(this).text();
    $('span#username').append(
    $('<a />', {
        text: sf
    }));
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<span id="username"></span>

</div>