7*4 2016-06-02 18:28 采纳率: 50%
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带有ajax的mysql [关闭]

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                    <p class="mb0 mt6">Closed <span title="2016-06-03 06:26:24Z" class="relativetime">3 years ago</span>.</p>
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Here is my code that I'm using.

ajax

$.ajax({
    type: "GET",
    url: "process.php",
    dataType: "html",
    success: function(data){
        $(".content").html(data);
    }
});

$("#submit").click(function(){
    $.ajax({
        type: "POST",
        url: "post.php",
        dataType: "html",
        success: function(data1){
            $(".content").html(data1);
        }
    });
});

process.php

<?php
$db = mysqli_connect("localhost","root","","webcap");
$query = mysqli_query($db,"SELECT * FROM test");
while($row = mysqli_fetch_assoc($query)){
    echo $row['num'];
}

post.php

<?php
$db = mysqli_connect("localhost","root","","webcap");
$num_query = mysqli_query($db,"SELECT * FROM test");
$num_row = mysqli_fetch_assoc($num_query);
$number = $num_row['num'];

$new_number = $number + 1;
$query2 = mysqli_query($db,"UPDATE test SET num='$new_number'");
echo $new_number;

The idea is when i click button it add plus one to my database and i can see it without refreshing but others don't.

I want that everyone in my website see it in real time without refreshing

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1条回答 默认 最新

  • weixin_33728708 2016-06-02 18:33
    关注

    If your ajax is only called in the javascript once, it won't update without refreshing. You need to put the ajax into setInterval and pick a refresh rate (ms):

    Interval = setInterval(function () {
    $.ajax({
        type: "GET",
        url: "process.php",
        dataType: "html",
        success: function(data){
            $(".content").html(data);
        }
    });
    }, 3000);
    
    评论

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