如何在单独的php脚本中使用$_POST提取名称？

Question

我正在进行一个使用jQuery/ajax从选定复选框中检索名称和值的项目。我在主页上使用php设置了复选框的名称和值，现在我希望在单独的php脚本中使用$_POST提取名称，这样我就可以使用这些名称从MySQL中删除项目。

$("#deleteproject").click(function () {
    var names = [];
    $('#projectcheckbox input:checked').each(function() {
        //all checkbox names are put in array
        names.push({name: $(this).attr('name'), value: $(this).val()});
    });
    alert($.param(names));
    return false;
});

上面的alert($.param)以val1.name和val1.value格式返回选中的复选框。

//run delete_project.php to erase projects from database
$.ajax({
    type: "post",
    url:"delete_project.php",
    data: names,
    cache: false,
    success:function() {
        alert(names + ' deleted')
    }
});

在过去的几天里，我一直在寻找答案，我希望有人能帮我解决这个问题。

Answer 1

I would prefer using html part in this way first, cos it's more flexible and easy in your case;

<input type="checkbox" name="projectcheckbox[]" value="foo_project" />
<input type="checkbox" name="projectcheckbox[]" value="bar_project" />
...

Or printing out the db results at first;

foreach ($projects as $project) {
   print '<input type="checkbox" name="projectcheckbox[]" value="'.$project.'" />';
}

Then calling jQuery.serialize will give you a data stuff like;

projectcheckbox[]=foo_project&projectcheckbox[]=bar_project ...

PHP part (after post);

foreach ((array) $_POST['projectcheckbox'] as $pro) {
   // do something with $pro = foo_project or bar_project etc...
   // THIS PART FOR SECURITY GUYS :)
   // BUT! DO NOT FORGET TO SECURE YOUR DATA ($pro) HERE!!!!!
}