℡Wang Yan 2020-02-18 02:43 采纳率: 100%
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Json对象数组

.ajax({
  cache: false,
    url: '/Dashboard/ListofNames',
    data: {
        charSearch: txtboxvalue
    },
    success: function (res){
        var obj = JSON.parse(res); //this object contains 1 index which is 0. 
        var parseObj = JSON.parse(obj[0].JsonResult) // This line is working i successfully gets the data from index 0
        var parseObj2 = JSON.parse(obj[1].JsonResult) //This is not working because index 1 is not existing, what i want is instead of getting an undefined exception, i want to set the index 1 into an empty string or whatever solution that i wont get any undefined exception.

    }
});

Any suggestion would really help me thanks.

  • 写回答

2条回答 默认 最新

  • ?Briella 2020-02-18 02:54
    关注
    Considering your JSON.parse of object given the response as this object.
    let res = [
        { name: "john", id: 1, JsonResult: "json-stringified-object-or-string" }
    ]
    JSON.parse(res[0] ? res[0].JsonResult : '""');
    JSON.parse(res[1] ? res[1].JsonResult : '""');
    
    评论

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