重做ajax功能

Question

Is there a way to make a function that converts default ajax function.

This is the ajax function i have

$.ajax({
    type: "POST",
    url: "http://" + document.location.host + '/userajax',
    data: 'type=register&name=' + name,
    beforeSend:function() {

    },
    success: function(response) {

    }
});

This is what i want it to look like

ajax('url', {
    method: 'get',
    parameters: {
        name: $('#name').val()
    },
    beforeSend: function() {

    },
    success: function(transport) {

    }
});

Ive tried to search on the internet but did not find anything

Answer 1

I don't think so. but you can do this:

$(document).ready(function(){

    var parameters = {
            name:       $("#name").val(),
            desc:       $("#desc").val()

        };

        $.ajax({
            url: 'path/to/file',
            data : parameters,
            beforeSend: beforeSubmit,
            dataType: "json",
            type : 'POST',
        })
        .done(function(data) {


        })
        .fail(function() {
            console.log("error");
        })
    })

Also note I don't set the function for the beforeSend directly in the call, I will create an externe function which gives me more freedom.

so I could do this:

function beforeSubmit(){
   if(something !== 'somethingelse'){
       return false; //ajax call will stop
   }else{
       return true; //ajax call
   }
}