weixin_33695082 2017-04-19 15:57 采纳率: 0%
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链接ajax文件[关闭]

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first of all thanks for reading.

Hi have a form which I'm trying to collect data through Ajax. I did it putting the ajax code into the <script> </script> tags and it worked fine. But when i moved it to a folder (js/registrarciu_ajax.js) and added <script src="js/registrarciu_ajax.js"> </script> it hasn't been working!.

Index.php linking tag

<script type="text/javascript" src="bootstrap/js/registrarciu_ajax.js"></script>

index.php form:

            <form method="POST" id="form-registrar-ciu" action="" class="form-horizontal">
            <div class="form-group">
                <label for="nombre_apellido">Nombre_Apellido</label>
                <input type="text" class="form-control" name="nombre_apellido" id="nombre_apellido" placeholder="Phillip_Rousseau">
            </div>
            <div class="form-group">
                <label for="dni">N° DNI/Pasaporte</label>
                <input type="text" class="form-control" name="dni" id="dni" placeholder="42393402">
            </div>
            <div class="form-group">
                <input type="text" class="form-control" name="edad" id="edad" for="edad" placeholder="Edad">
            </div>
            <div class="form-group">
                <input type="text" class="form-control" name="residencia" id="residencia" for="residencia" placeholder="LS/SF/LV">
            </div>
            <input class="btn btn-success" id="registrar-btn" type="button" value="Registrar"> Registrar ciudadano>
        </form>

Ajax code:

 $(document).ready(function(){
$("#registrar-btn").click(function(){
    var nombre_apellido = $("#nombre_apellido").val();
    var dni = $("#dni").val();
    var edad = $("#edad").val();
    var residencia = $("#residencia").val();
    // Returns successful data submission message when the entered information is stored in database.
    var dataString = 'nombre_apellido1='+ nombre_apellido + '&dni1='+ dni + '&edad1='+ edad + '&residencia1='+ residencia;
    if(nombre_apellido==''||dni==''||edad==''||residencia=='')
    {
        alert("Please Fill All Fields");
    }
    else
    {
        // AJAX Code To Submit Form.
        $.ajax({
        type: "POST",
        url: "registrar_ciu.php",
        data: dataString,
        cache: false,
        success: function(result){
        alert(result);
        }
});
}
return false;
});
});

I don't think it's necessary to put the .php file who refer the ajax code, because it works fine. The problem is that when I click the form's button, it doesn't refer to the .js file which is in the 'js' folder (but it works if the ajax code is in the same file of the form, into 'scripts' tag>

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  • weixin_33690963 2017-04-19 16:20
    关注

    if you are not, then simply add this before the script tag you are calling the js file from

    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.0/jquery.min.js"></script>
    

    or any other jquery library you prefer; You need jQuery library in order to run jQuery

    评论

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