重定向到AJAX URL

Question

Have to redirect to the below URL:

AjaxView1?catalogId=12345&storeId=67890&List=123#AjaxView2?ListId=123&storeId=67890&catalogId=12345

I am passing this value as hidden prameter in form and redirecting from a java class. Somehow, the AJAX view is not being picked up. It is redirecting to the former AJAXView1.

Can you please suggest what I need to change so that it gets redirected to a second AJAX view "Ajaxiew2".

I would like to know, how will it handle the # symbol in the URLredirection.

EDIT

I have a form from where I am passing the hidden parameter value of URL.

<form name ="LogonList" action="someActionCode"  method="post">
<input type="hidden" name="storeId" value="67890">
<input type="hidden" name="URL" value="AjaxView1?catalogId=12345&storeId=67890&List=123#AjaxView2?ListId=123&storeId=67890&catalogId=12345 >
<input type="submit" value="Submit"/>

someActionCode will call a java class which will perform some business logic and after business logic gets executed, it will redirectURL to the URL passed as hidden parameter.

I would like to know, how will it handle the # symbol in the URLredirection.

Answer 1

Passing second url as hidden value first do the firstURL work then do any one of the below.

response.sendRedirect("/url2");

or use this one based on the situation where you want

String destination = "url2";
RequestDispatcher rd = getServletContext().getRequestDispatcher(destination);
rd.forward(request, response);

or use this one based on the situation where you want

String destination = "url2";
RequestDispatcher rd = getServletContext().getRequestDispatcher(destination);
rd.include(request, response);