先找出相同行的id，sql如下：

SELECT
    DISTINCT(t_s.id)
FROM
    `t_score` t_s
    INNER JOIN ( SELECT * FROM t_score ) AS ts ON t_s.NAME = ts.NAME 
    AND t_s.score = ts.score 
    AND t_s.id != ts.id
    order by t_s.id asc;

如果删除的话，在这个基础上，再加一层删除操作：

DELETE 
FROM
    t_score 
WHERE
    id IN (
    SELECT
        a.id 
    FROM
        (
        SELECT DISTINCT
            ( t_s.id ) AS id 
        FROM
            `t_score` t_s
            INNER JOIN ( SELECT * FROM t_score ) AS ts ON t_s.NAME = ts.NAME 
            AND t_s.score = ts.score 
            AND t_s.id != ts.id 
        ORDER BY
            t_s.id ASC 
        ) a 
    );

亲测有效，希望可以帮助你！（不要忘了给分哦！）

select DISTINCT from table

select * from tab t
where (t.name,t.score) in (select name,score from tab group by name,score having count(*)> 1 -- 查询重复的数据
and rowid not in (select min(rowid) from tab group by name,score having count(*)>1); -- 加上这个可以保留一个

rowid 是oracle的唯一标识 mysql用_rowid试下

删除就是把查到的删掉就行

查询：
select * from test where id not in( select MAX(id) as id from test group by name, score) //test改为你自己的数据库名
删除：
delete from test where id in (
select test1.id from test as test1, test as test2 where test1.name = test2.name and test1.score = test2.score and test1.id < test2.id)
应该还是挺容易理解的

试试看
--select
select * from your_table where id in (select max(id) from your_table group by name, score having count(id)>1)
--delete
delete from your_table where id in (select max(id) from your_table group by name, score having count(id)>1);