C语言入门问题，两个几乎一样的代码，运行结果不同？

Question

问题：现有n块砖，要由n人一次搬完，假定男人一次可以搬4块，女人一次可以搬3块，两个小孩搬1块，计算这n人中男人、女人和小孩的人数。输入人数和砖数n，输出可能的解决方案。

我自己用C写了一个，但是无法运行，网上找的C++的那个就对了，我感觉这两串代码都一样啊，这是为啥？
还有为什么在中间的时候要用 XYZ重新规定一下数据？否则结果就结果不对。

无法运行的代码

#include <stdio.h>

int main()
{
    int n;
    int man,woman,children;
    int x,y,z;
    scanf("%d",&n);
    for ( man = 0; man <= n/4; man++)
    {
        for (woman = 0; woman <= n/3; woman++)
        {
            children = 2 * (n - 4 * man - 3 * woman);    
            if (children>0 && children == n - man - woman ) 
            {
                x = man; y = woman; z = children;
                printf("man%d\nwoman%d\nchildren%d\n",man,woman,children);
            }

        }
    }
     if( x==0||y==0||z==0)
     printf("no result");
    return 0;
}

可以运行的代码

#include <iostream>
#include <cmath>
#include<stdlib.h>
using namespace std;
int main()
{
    int men, women, children;
    int n;
    int x, y, z;
    cin >> n;
    for (men = 0; men <= n / 4; men++)
    {
        for (women = 0; women <= n / 3; women++)
        {
            children = 2 * (n - 4 * men - 3 * women);
            if (children>0 && children == n - men - women)
            {
                x = men; y = women; z = children;
                cout << "men" << men << endl;
                cout << "women" << women << endl;
                cout << "children" << children << endl;
            }
        }
    }
    if (x == 0 || y == 0 || z == 0)
        cout << "no result!" << endl;
    system("pause");
    return 0;
}

Answer 1

你把
printf("man%d\nwoman%d\nchildren%d\n",man,woman,children);

换成 3 个printf试试?